Integrand size = 23, antiderivative size = 94 \[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{5/2}} \, dx=-\frac {2 b}{5 f (d \sec (e+f x))^{5/2}}+\frac {6 a E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{5 d^2 f \sqrt {\cos (e+f x)} \sqrt {d \sec (e+f x)}}+\frac {2 a \sin (e+f x)}{5 d f (d \sec (e+f x))^{3/2}} \]
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Time = 0.09 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.174, Rules used = {3567, 3854, 3856, 2719} \[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{5/2}} \, dx=\frac {6 a E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{5 d^2 f \sqrt {\cos (e+f x)} \sqrt {d \sec (e+f x)}}+\frac {2 a \sin (e+f x)}{5 d f (d \sec (e+f x))^{3/2}}-\frac {2 b}{5 f (d \sec (e+f x))^{5/2}} \]
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Rule 2719
Rule 3567
Rule 3854
Rule 3856
Rubi steps \begin{align*} \text {integral}& = -\frac {2 b}{5 f (d \sec (e+f x))^{5/2}}+a \int \frac {1}{(d \sec (e+f x))^{5/2}} \, dx \\ & = -\frac {2 b}{5 f (d \sec (e+f x))^{5/2}}+\frac {2 a \sin (e+f x)}{5 d f (d \sec (e+f x))^{3/2}}+\frac {(3 a) \int \frac {1}{\sqrt {d \sec (e+f x)}} \, dx}{5 d^2} \\ & = -\frac {2 b}{5 f (d \sec (e+f x))^{5/2}}+\frac {2 a \sin (e+f x)}{5 d f (d \sec (e+f x))^{3/2}}+\frac {(3 a) \int \sqrt {\cos (e+f x)} \, dx}{5 d^2 \sqrt {\cos (e+f x)} \sqrt {d \sec (e+f x)}} \\ & = -\frac {2 b}{5 f (d \sec (e+f x))^{5/2}}+\frac {6 a E\left (\left .\frac {1}{2} (e+f x)\right |2\right )}{5 d^2 f \sqrt {\cos (e+f x)} \sqrt {d \sec (e+f x)}}+\frac {2 a \sin (e+f x)}{5 d f (d \sec (e+f x))^{3/2}} \\ \end{align*}
Time = 1.42 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.79 \[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{5/2}} \, dx=\frac {2 \sqrt {d \sec (e+f x)} \left (3 a \sqrt {\cos (e+f x)} E\left (\left .\frac {1}{2} (e+f x)\right |2\right )+\cos ^2(e+f x) (-b \cos (e+f x)+a \sin (e+f x))\right )}{5 d^3 f} \]
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Result contains complex when optimal does not.
Time = 6.15 (sec) , antiderivative size = 438, normalized size of antiderivative = 4.66
method | result | size |
default | \(\frac {2 a \left (3 i \cos \left (f x +e \right ) E\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}-3 i \cos \left (f x +e \right ) F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}+6 i \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, E\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}-6 i \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}+3 i \sec \left (f x +e \right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, E\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right )-3 i \sec \left (f x +e \right ) \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}+\sin \left (f x +e \right ) \left (\cos ^{2}\left (f x +e \right )\right )+\sin \left (f x +e \right ) \cos \left (f x +e \right )+3 \sin \left (f x +e \right )\right )}{5 f \left (\cos \left (f x +e \right )+1\right ) \sqrt {d \sec \left (f x +e \right )}\, d^{2}}-\frac {2 b}{5 f \left (d \sec \left (f x +e \right )\right )^{\frac {5}{2}}}\) | \(438\) |
parts | \(\frac {2 a \left (3 i \cos \left (f x +e \right ) E\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}-3 i \cos \left (f x +e \right ) F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}+6 i \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, E\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}-6 i \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}+3 i \sec \left (f x +e \right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}\, \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, E\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right )-3 i \sec \left (f x +e \right ) \sqrt {\frac {\cos \left (f x +e \right )}{\cos \left (f x +e \right )+1}}\, F\left (i \left (\csc \left (f x +e \right )-\cot \left (f x +e \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (f x +e \right )+1}}+\sin \left (f x +e \right ) \left (\cos ^{2}\left (f x +e \right )\right )+\sin \left (f x +e \right ) \cos \left (f x +e \right )+3 \sin \left (f x +e \right )\right )}{5 f \left (\cos \left (f x +e \right )+1\right ) \sqrt {d \sec \left (f x +e \right )}\, d^{2}}-\frac {2 b}{5 f \left (d \sec \left (f x +e \right )\right )^{\frac {5}{2}}}\) | \(438\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.10 (sec) , antiderivative size = 111, normalized size of antiderivative = 1.18 \[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{5/2}} \, dx=\frac {3 i \, \sqrt {2} a \sqrt {d} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (f x + e\right ) + i \, \sin \left (f x + e\right )\right )\right ) - 3 i \, \sqrt {2} a \sqrt {d} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (f x + e\right ) - i \, \sin \left (f x + e\right )\right )\right ) - 2 \, {\left (b \cos \left (f x + e\right )^{3} - a \cos \left (f x + e\right )^{2} \sin \left (f x + e\right )\right )} \sqrt {\frac {d}{\cos \left (f x + e\right )}}}{5 \, d^{3} f} \]
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\[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{5/2}} \, dx=\int \frac {a + b \tan {\left (e + f x \right )}}{\left (d \sec {\left (e + f x \right )}\right )^{\frac {5}{2}}}\, dx \]
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\[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{5/2}} \, dx=\int { \frac {b \tan \left (f x + e\right ) + a}{\left (d \sec \left (f x + e\right )\right )^{\frac {5}{2}}} \,d x } \]
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\[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{5/2}} \, dx=\int { \frac {b \tan \left (f x + e\right ) + a}{\left (d \sec \left (f x + e\right )\right )^{\frac {5}{2}}} \,d x } \]
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Timed out. \[ \int \frac {a+b \tan (e+f x)}{(d \sec (e+f x))^{5/2}} \, dx=\int \frac {a+b\,\mathrm {tan}\left (e+f\,x\right )}{{\left (\frac {d}{\cos \left (e+f\,x\right )}\right )}^{5/2}} \,d x \]
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